I am having a problem with this force equation since it does not state an acceleration but there is a constant velocity. Any help?(adsbygoogle = window.adsbygoogle || []).push({});

Also it does not state any force applied. All i can figure out is normal force and gravitational force.

Here the equation:

A 1500 kg car driving over a dry asphalt surface at a constant speed of 25m/s. There is static friction because you have your anti lock breaks on.

All I know is that the applied force due to constant velocity equals the weight of the car.

From what I know Normal Force Gravitational force is equal so

(9.81 m/s^2)(1500kg)= 14,715N

Then used The equation Ff = u Fn = (0.85)(14,715N) = 12507.75 N which is the force of friction.

Since the force of the applied force and the force of friction are going in opposite directions I subtracted 14,715- 12507.5 and used the Fnet=ma equation getting 1.465 m/s^2.

Would this make sense?

The question:

What is the force of the car?

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# Homework Help: Force due To Fricton

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