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Force due to inertia

  1. Oct 20, 2010 #1
    1. The problem statement, all variables and given/known data

    Hi guys, I have a very beginner question:

    Lets say we have a block(147mm*241mm) of mass M=5.1kg resting on a frictionless surface.
    Now if a force of F, 483N is applied to one corner(A) of the block, the latter moves in a horizontal plane and at this instant the block does not have angular velocity.
    How do we calculate the x-component of the acceleration of the opposite corner(B)??

    I know i have to find the moment of inertia which i did using : 5.1/12 *(147^2+241^2)... then what should i do??

    2. Relevant equations
    Equation for inertia: M/12(L^2+b^2)

    f=force due to inertia
    3. The attempt at a solution

    I have only calculated the inertia and i do not know how to continue
  2. jcsd
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