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Force Equilibrium

  1. Feb 11, 2009 #1
    1. The problem statement, all variables and given/known data
    (Intro 1 figure) A chandelier with mass m is attached to the ceiling of a large concert hall by two cables. Because the ceiling is covered with intricate architectural decorations (not indicated in the figure, which uses a humbler depiction), the workers who hung the chandelier couldn't attach the cables to the ceiling directly above the chandelier. Instead, they attached the cables to the ceiling near the walls. Cable 1 has tension T1 and makes an angle of theta1 with the ceiling. Cable 2 has tension T2 and makes an angle of theta2 with the ceiling.
    MFS_1l_3_v1_a.jpg

    Find an expression for T1, the tension in cable 1, that does not depend on T2.
    Express your answer in terms of some or all of the variables m, theta1, and theta2, as well as the magnitude of the acceleration due to gravity g.


    2. Relevant equations
    T1 SHOULD equal: mg/ (sin theta 1 + (cos theta 1/cos theta 2)* sin theta 2), but any time I put in sin they say that I haven't formatted the equation right.
    what am I missing that can only be computed by thetas 1 & 2 as well as m and g?
     
  2. jcsd
  3. Feb 12, 2009 #2

    tiny-tim

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    Hi enantiomer1! :smile:

    (have a theta: θ :wink:)
    hmm … looks ok to me :confused:

    maybe they want you to keep (θ1 + θ2) as it is?
     
  4. Feb 12, 2009 #3
    Maybe there's a shortage of brackets to make the expression clear?

    mg/ (sin theta 1 + ((cos theta 1/cos theta 2)* sin theta 2))

    BTW I can't see how you got your expression..;={

    Since the chandelier isn't moving, it must be that the horizontal component of T1 is equal to the horizontal component of T2. So we can derive an expression for T2 in terms of T1.

    Then we equate mg to the vertical components of T1 and T2, and then substitute for T2.

    That gives me...

    T1 = mg*(cos theta2)/((sin theta1)*(cos theta2) + (sin theta2)*(cos theta1))

    NO it's the same, just prettier!
     
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