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Force exerted

  1. Oct 21, 2007 #1

    jlk

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    I'm uncertain how to find the normal force the floor exerts on the dolly (part B) and the force the dolly exerts on the floor (part C) because the mass of the dolly was not given. ONly the combined mass of the dolly and carton was given.

    1. The problem statement, all variables and given/known data
    A stock clerk pushes a carton on a dolly. Refer to image
    [​IMG]

    The carton and dolly have a combined mass of 23 kg. The carton and dolly undergo an acceleration of 0.41 m/s2.
    (a) Find the magnitude of the force exerted by the clerk.
    (b) Find the magnitude of the normal force that the floor exerts on the dolly.
    (c) Find the magnitude of the normal force that the dolly exerts on the floor.


    carton and dolly Mass = 23 kg
    carton and dolly A = .41 m/s2

    g = 9.8m/s2


    2. Relevant equations
    F = ma
    Fx = max [in x direction]
    Fy= may [in y direction]

    fmc = force of man on carton
    fmcx = fmc* cos 37 [in x direction]
    fmcy = fmc* sin 37 [in y direction]


    3. The attempt at a solution


    Part A) SLOVE for FMC

    fmc = force of man on carton

    m in this case is the combine mass of the dolly and carton = 23 kg.

    Fx = max [in x direction]

    fmc = (23kg * 0.41 m/s2) / cos 37
    fmc = 11.807 N
     
    Last edited: Oct 21, 2007
  2. jcsd
  3. Oct 21, 2007 #2
    Do you see any reason to not consider the dolly and the carton one entity?
     
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