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Force exerted

  1. Sep 13, 2009 #1
    1. The problem statement, all variables and given/known data
    A charged particle A exerts a force of 2.62 micro newtons to the right on charged particle B when the particles are 13.7 mm apart. Particle B moves straight away from A to make the distance between them 17.7 mm. What vector force does it exert on A?

    using coulombs law: (8.99x10^9)(2.62x10^-6)^2/(1.77x10^-2)^2

    did I set this up right? if not what did I do wrong?


    2. Relevant equations

    coulombs law: F=k q1q2/r^2

    3. The attempt at a solution

    (8.99x10^9)(2.62x10^-6)^2/(1.77x10^-2)^2

    did I set this up right? if not what did I do wrong?
     
  2. jcsd
  3. Sep 15, 2009 #2

    Redbelly98

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    Homework Helper

    We don't know that the charges are 2.62 μC. The 2.62x10^-6 refers to the force, in Newtons.

    You're correcting in using the equation,

    F = k q1 q2 / r2

    We don't know q1 or q2 here.
     
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