# Force help me please =)

1. Apr 21, 2007

### skittlez411

1. The problem statement, all variables and given/known data

It's moving day and you need to push a 100kg box up a 20 degree ramp into the truck. The coefficients of friction for the box on the ramp are Us=0.9 and Uk=0.6. Your largest pushing force is 1000N. Can you get the box into the truck without assistance if you get a running start at the ramp? If you stop on the ramp, will you be able to get the box moving again?

2. Relevant equations

Fk=Ukmg
F=mgsin20

3. The attempt at a solution

a) Fk=(0.6)(100)(9.8)
=588N

F=mgsin20
=335N

yes, my maximum pushing force is 1000N. 335N<1000N

b) Fs=Usmg
=882N

Yes. I will be able to get the box moving again because I have enough force to overcome the static force.

thank you!!!!!!

2. Apr 21, 2007

### Staff: Mentor

Careful here! Fk = Uk N, where N is the normal force. Since the mass is on an incline, the normal force is not just mg.

3. Apr 21, 2007

### skittlez411

ok... so i got

a) Fk=ukmgsin20
= 201.11 N

so if i get a running start i would be able to move the box up w/o assistance.

b) Fs= Usmgsin20
= 301.66 N

If i stop at the ramp, i will be able to get the box moving agian.. 301.66N<1000N

is that it??? thanks!

4. Apr 21, 2007

### pcdagr8

N is mgcos 20:rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl:

5. Apr 21, 2007

### skittlez411

can i ask why? i thought it's sine...

6. Apr 21, 2007

### pcdagr8

N is normal reaction ,component of gravity perpendicular to the surface
when you are taking the component of gravity parallel to the surface as mgsin20
how are you missing out that perpendicular component will be mg cos20
just draw a free body diagram and resolve the forces....

7. Apr 21, 2007

### skittlez411

hmmm...... i still dont quite get it. i know how sine and cosine are. but i dont quite get the diagram... sorry!

8. Apr 21, 2007

### Staff: Mentor

9. Apr 21, 2007

### pcdagr8

well...i can't help u with this.i don't have any software to make a diagram for you....may be someone else can help...

10. Apr 21, 2007

### skittlez411

ok thanks austronuc and pcdagr8! i get that part now!

a) Fk=Ukmgcos20
= 552.5N

b) Fs=Usmgcos20
=828.8N

so this is what i have right now.

11. Apr 22, 2007

### ImsoFly

good job

12. Apr 22, 2007

### skittlez411

yay! i got it? thanks!