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Force integration for work

  1. Feb 20, 2013 #1
    A 2.3 kg block is acted upon by a horizontal force F(x) = 25.0 - 10.0x where the force is measured in Newtons if x is measured in meters. The coefficient of kinetic friction between the block and the flat surface is 0.21. The block is initially at x = 0 m. What distance must the block travel if the net work done on the block by F(x) and friction combined is to be exactly zero?


    Work=Fd
    Force(friction)=mu x mg



    The net work has to equal 0 so i set up the problem like this:
    Wnet= Wfriction-Wf(x)=0
    Wf(x)=Wfriction
    F(x)d=Ffd (the d's cancel out)
    25-10x=mu x mg (plug in numbers and solve for x)
    x=2.026 m
    I feel like I'm on the right track of how to solve the problem but my x is wrong.
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Feb 20, 2013 #2

    SammyS

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    F(x) is not constant, so the work done by F(x) is not simply F(x)d .

    You must integrate F(x)dx.
     
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