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Force needed to hold together a capacitor
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[QUOTE="phantomvommand, post: 6465431, member: 687416"] Thank you for your reply. Why would it be sigma/2e0 though? The plates are insulating here, so the charge of Q remains solely on 1 side of the plate. The other side has 0 charge. Thus, the E-field in the region in between is 0 (as the inner surface of the other plate creates a similar field in opp direction.) However, the E-field in the region to the left of plate 1 is due to the E-field of plate 2, which is sigma/e0 leftwards. Thus, the average E-field around plate 1 is given by (0 + sigma/e0) /2. The force on plate 1 is in fact due to the field of plate 2. [/QUOTE]
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Force needed to hold together a capacitor
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