1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Force of a Dipole

  1. Oct 16, 2013 #1
    1. The problem statement, all variables and given/known data
    A dipole is centered at the origin, and is composed of charged particles with charge +e and -e, separated by a distance 7 ✕ 10-10 m along the y axis. The +e charge is on the -y axis, and the -e charge is on the +y axis. A proton is located at <0, 3 ✕ 10-8, 0> m. What is the force on the proton, due to the dipole?

    2. Relevant equations
    E=k*[(2*q*s)/(r^3)]
    F=E*q


    3. The attempt at a solution
    I calculated the electric field using the equation for a charged particle on axis with a dipole. I then multiplied that electric field by the charge of the proton(1.6e-19)
    I'm very lost with all this dipole stuff. Any and all help is appreciated!
     
  2. jcsd
  3. Oct 16, 2013 #2

    gneill

    User Avatar

    Staff: Mentor

    Show the equation that you used. Sketch the relative positions of the particles. Hint: you'll only need one axis to do it!
     
  4. Oct 16, 2013 #3
    What I have is k=9e9
    q=-1.6e-19
    s=7e-10
    r=(3e-8)-(7e-10/2)=2.965e-8
    E=-77342.2N/C
    The charge of the proton is 1.6e-19
    I think the force should therefore be (0,1.6e-19*-77342.2,0)=(0,-1.237e-14,0).
    But that's just not working:(
     
  5. Oct 16, 2013 #4

    gneill

    User Avatar

    Staff: Mentor

    What coordinate axis are the dipole electrons on?

    What coordinate axis is the proton on?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Force of a Dipole
  1. Force of a dipole (Replies: 9)

  2. External forces dipole (Replies: 5)

  3. Force due to a Dipole (Replies: 1)

Loading...