- #1
mopar969
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The Yukawa-type potential energy function for the interaction of a particular pair of neutrons in an atomic nucleus is U(r) = -(a/r)U(sub o) (e^(-r/a)) where U(sub o) = 5 x 10^(-12) J and a = 1.5 x10^(-15) m. Find the force as a function of r, then evaluate the force for r=a and r=3a.
To get force I took Force = -du/dr and got -a(r^-2)(U(subo))(e^(-r/a)). Then I plugged a in for r in the derivative and got -3333.33(e^(-1)). Then I plugged 3a in for r in the derivative and got -0.37037(e^(3)). Is my approach to this problem correct and are my answers correct?
To get force I took Force = -du/dr and got -a(r^-2)(U(subo))(e^(-r/a)). Then I plugged a in for r in the derivative and got -3333.33(e^(-1)). Then I plugged 3a in for r in the derivative and got -0.37037(e^(3)). Is my approach to this problem correct and are my answers correct?