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Force of repulsion

  1. Sep 12, 2016 #1
    1. The problem statement, all variables and given/known data
    two similar charged bodies are kept 5 cm apart in air. If the second body is shifted away from the first another 5 cm, there force of repulsion will be?

    2. Relevant equations
    Coulomb's law? F= k (q1q2)/r^2?
     
  2. jcsd
  3. Sep 12, 2016 #2

    Drakkith

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    Staff: Mentor

    What do you think? What are your thoughts on this problem? What does Coulomb's law govern?
     
  4. Sep 12, 2016 #3
    force of attraction or repulsion is directly proportional to product of charges and inversely proportional to square of the distance between them. So....if the r is moved by another 5 cm r^2 also increases.
    When r= 5 r^2 = 25
    When r=10 then r^2 is 100
    Since it is inversely proportional the force reduces by 1/4. True?
     
  5. Sep 12, 2016 #4

    Drakkith

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    Staff: Mentor

    Yep! When you double the distance, you reduce the force to 1/4 of its original strength. If you triple the distance, the force is reduced to 1/9 the strength.
     
  6. Sep 12, 2016 #5
    I was not sure if my answer was correct or not. Now I know. Thank you for your time.
     
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