Calculate Force on Golf Ball Impact

[LOannie234]

A golf ball (m = 71.7 g) is struck a blow that
makes an angle of 43.1 with the horizontal.
The drive lands 122 m away on a flat fairway.
The acceleration of gravity is 9.8 m/s^2

If the golf club and ball are in contact for 6.62 ms, what is the average force of impact?
Neglect air resistance.

 

[tiny-tim]

LOannie234, you know the https://www.physicsforums.com/showthread.php?t=414380" …

show us what you've tried, and where you're stuck, and then we'll know how to help!

 

[LOannie234]

i tried to do 71.7(vx-v0x)/delta t and 71.7(vy-v0y)/delta t but i don't know where to go after that

 

[tiny-tim]

You need to find the initial speed, v.

Then you can find the acceleration during the impact, and multiply by the mass to get the force.

Goodnight! :zzz:​

 

[rwisz]

To calculate the force on the golf ball during impact, we can use the equation F = m*a, where F is the force, m is the mass, and a is the acceleration. In this case, the mass of the golf ball is 71.7 g, or 0.0717 kg. The acceleration is due to gravity, which is 9.8 m/s^2. We also know that the ball is in contact with the club for 6.62 ms, or 0.00662 s.

First, we need to find the horizontal and vertical components of the initial velocity of the ball. We can use trigonometry to do this:

Horizontal component: v_x = v*cos(43.1) = 122 m/s * cos(43.1) = 87.58 m/s
Vertical component: v_y = v*sin(43.1) = 122 m/s * sin(43.1) = 87.58 m/s

Next, we can use the equation d = v_i*t + (1/2)*a*t^2 to find the vertical displacement of the ball during impact. In this case, the initial velocity is v_y = 87.58 m/s, the time is t = 0.00662 s, and the acceleration is due to gravity, a = -9.8 m/s^2. Plugging in these values, we get:

d = 87.58 m/s * 0.00662 s + (1/2)*(-9.8 m/s^2)*(0.00662 s)^2 = 0.29 m

Now, we can use this vertical displacement to calculate the average force of impact using the equation F = m*a. In this case, the mass of the ball is 0.0717 kg and the acceleration is due to gravity, -9.8 m/s^2. Plugging in these values, we get:

F = 0.0717 kg * (-9.8 m/s^2) = -0.7 N

Since we are neglecting air resistance, the average force of impact on the ball is approximately -0.7 N. This means that the ball experiences a downward force of 0.7 N during impact. It is important to note that this value may not be entirely accurate due to the assumptions and approximations made in the calculations. Further experimentation and data