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Force on a rod

  1. Mar 20, 2012 #1
    Suppose I have a metal rod in empty space with a uniform mass distribution. Suppose a force acts perpendicular to the rod at some distance R from the rod's centre of mass over some time Δt. There are no other forces acting on the rod.

    (1) What type of motion will the rod have over Δt? Will the rod rotate about the point where the force acts, or will it have some other type of motion?

    (2) How much of the work done on the rod will be converted to translational kinetic energy and how much will be converted to rotaional kinetic energy?

    Note that the force does not change direction even as the rod rotates - ie it only acts perpendicular to the rod at the start of its motion.

    Thank You.

    BTW - This question is theoretical in nature - ie it doesn't require a calculation so I don't think it counts as a "homework" type question. I've been thinking about this for some time now. Nevertheless, I apologise if I've placed it in the wrong section.
     
  2. jcsd
  3. Mar 20, 2012 #2

    berkeman

    User Avatar

    Staff: Mentor

    Welcome to the PF.

    Are you familiar with Free Body Diagrams (FBDs)? Are you familiar with moments and the Moment of Inertia (MOI) of a rod?
     
  4. Mar 20, 2012 #3
    We've just covered basic mechanics at uni (I'm doing first year physics). We've finished all topics in both the translational and rotational aspects of mechanics, including force diagrams and rotational inertia.

    I know that the angular acceleration of the rod will be the quotient of the acceleration and the distance the force was exerted from the centre of mass. From here we can find the angular velocity after Δt, hence the rod's rotational kinetic energy. We can then subtract the rotational kinetic energy from the total work done to the system to find the translational kinetic energy.

    After I've removed the force the rod will move in a straight line and rotate about its centre of mass, but what will be its motion over Δt? And why does the rod gain rotational acceleration equal to α / R? I can calculate how much rotational energy the system gains only once I know that this statement is true (I want to know why its true).

    Thank you
     
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