Ok there is a dam of width "b" and water is fille don one side of it to a height h . Now i need to calculate the force on the wall of the dam on the side where water is filled .(adsbygoogle = window.adsbygoogle || []).push({});

This is what I did:

I considered a small layer of water of dx (vertical) at a distance x from top of water surface .

Then:

[itex] \int dF= \int \delta xg (bdx)[/itex]

Limits 0--->h on RHS

[itex] F=\frac {b \delta gh^2}{2} [/itex]

Therefore the force on the wall depends on :

Width of the dam

The height "h" to which water is filled

Density of water

and g

But one thing i noticed is that the force on the wall doesnt depend on the length of the river..!

2) Now suppose i want to calculate force due to water ina cuboid lying horizontally on floor ..Its length is l breadth is b and height h ... now if it lies on floor with breadth as its height...then it means as per previous conclusion that length of the cuboid lying horizontally wouldnt make any difference...So this means i keep on increasing its length without any effect on force due to water on the front face?

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# Homework Help: Force on a water container

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