1. The problem statement, all variables and given/known data A gun weighs 10lbs and the barrel length is 10.2 inches. It fires a .45 caliber bulect weighing .0328lbs at a speed of 918ft/s. How much force is exerted on the bullet when fired? 2. Relevant equations F=ma 3. The attempt at a solution Here is what I did. Keep in mind that it is wrong, but when I did it I believed it to the correct method. Vi=0 vf=918 s=.85 ft a=? 918^2=1.7a a=495720ft/s(squared) F=ma F=.3105kg(495720) F=153921.06 N TRIED IT AGAIN: MbAb=MgAg (.001018634)(495720)=.3105a a=1626.27 F=ma F=(.3105)(1626.27) F=504.95(aprox.) Is this correct? If not, what should I do instead?