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bob24
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Homework Statement
A gun weighs 10lbs and the barrel length is 10.2 inches. It fires a .45 caliber bulect weighing .0328lbs at a speed of 918ft/s. How much force is exerted on the bullet when fired?
Homework Equations
F=ma
The Attempt at a Solution
Here is what I did. Keep in mind that it is wrong, but when I did it I believed it to the correct method.
Vi=0
vf=918
s=.85 ft
a=?
918^2=1.7a
a=495720ft/s(squared)
F=ma
F=.3105kg(495720)
F=153921.06 N
TRIED IT AGAIN:
MbAb=MgAg
(.001018634)(495720)=.3105a
a=1626.27
F=ma
F=(.3105)(1626.27)
F=504.95(aprox.)
Is this correct?
If not, what should I do instead?
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