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Force on carts

  1. Nov 19, 2004 #1
    There is a1kg cart with a 0.5kg cart attached to it. There is an applied force of 4N on the 1kg cart:

    --4N-->[1kg][0.5kg]

    What is the force on the 1kg cart due to the 0.5 kg cart?
    F=ma
    4N=1.5a
    a=2.67m/s^2

    F=ma
    F=(0.5)(2.67m/s^2)
    F=1.3

    What is the force on the 0.5kg cart due to the 1 kg cart?
    F=ma
    F=(1)(2.67m/s^2)
    F=2.67N

    is this correct?
     
  2. jcsd
  3. Nov 19, 2004 #2
    Looks good to me.
     
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