A heavy ring of mass m is clamped on the periphery of a light circular disc. A small particle of equal mass is placed at the center of the disc. The system is rotated in such a way that the center moves in a circle of radius r and with a uniform speed v. Find the external force on the system.
- Finding the Center of Mass of the system:
mr/(m+m) => r/2
Therefore the center of mass lies at r/2 from the center
- Finding force on the system:
Putting r=r/2 (i.e.the center of mass), F=2mv2/r
The Attempt at a Solution
It is known to us the position of the center of mass of the system. Therefore the force on the system must be equivalent that on the center of mass. Using this, i formulated the possible expression for the external force on the system. But I am still confused whether my approach is correct.
Any feedback is deeply valued and appreciated