Can someone tell me if im on the right track with this.(adsbygoogle = window.adsbygoogle || []).push({});

Problem: Two parallel conductors are 15cm apart and carry current of 8 amp and 12 amp. Calculate the size and direction of the force that the conductors exert on each one meter length of each other.

8 amp (out of page) o -------- 15cm --------- x (into page) 12 amp

My attempt:

Left conductor

B=K x (i/d)

B=2x10^-7 x (8/.15)

B=1.06666 x 10^-5

Right conductor

B=K x (i/d)

B=2x10^-7 x (12/.15)

B=1.6 x 10^-5

Since the currents are moving in opposite directions minus the smaller teslas from the larger.

1.6x10^-5 - 1.06666 x 10^-5 = 5.3334 x 10^-6

Only the 8amp conductor will experience a force.

F=BiL

F=5.3334 x 10^-6 x 8 x 1

= 4.26672 x 10^-5 N

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Force on conductors

**Physics Forums | Science Articles, Homework Help, Discussion**