A cubic metal box with sides 32.0 cm contains air at a pressure of 1.00 atm and a temperature of 294 K. The box is sealed so that the volume is constant and it is heated to a temperature of 396K. Find the force on each wall of the box due to the increased pressure within the box. [The outside air is at 1 atm of pressure.](adsbygoogle = window.adsbygoogle || []).push({});

I started out PV=nRT

volume of the box = .32^3=0.328m^3*(1L/1x10^-3)=32.8L

n=PV/RT

1atm(32.8L)/(.08207 atm L/mol*K)(294K)=1.36mol

P=nRT/V

[1.36mol(.08207 atm L/mol*K)396K]/32.8L

=1.35 atm

F=P*A

=1.35 atm*.32^2=.138

**that isnt the correct answer

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# Homework Help: Force on each wall of a box

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