- #1

Tanya Back

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I am having trouble doing this question-->

A gardener exerts a force of 150 N [ 22 degrees below the horizontal] in pushing a large 18 Kg box a distance of 1.6 m. The coefficient of kinetic friction between the box and the floor is 0.55.

Question -->

Use Newton's law to determine magnitudes of the normal force and force of friction on the box?

Solution :

Fn= Fag perpendicular

= Fgcosa

= (9.8)(18)cos22

= 164 N

Ff= uFn

=0.55(164)

= 89.9 N

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My answers are wrong becasue the answer is suppose to be Fn = 230 N and Ff= 130 N

What did i do wrong? how can i fix it?