Force Problem with blocks

1. Sep 15, 2014

The Wanderer

1. The problem statement, all variables and given/known data
Tom now pushes eight identical blocks on the horizontal and frictionless table (he’s compulsive). The force that block 1 exerts on block 2 is F12; the force that block 7 exerts on block 8 is F78. What is the ratio F12/ F78?
2. Relevant equations
F=ma
Δp = FnetΔt

3. The attempt at a solution
So really my problem is just understanding why the ratio isn't 1. I have no idea how to work it out... this is my attempt and I'm not sure if it is correct.

The force block 1 exerts on block 2 would just be mass*acceleration of the first block. However the force block 7 exerts on block 8 would be mass of one block*7*acceleration as the mass of all the first 7 blocks are being pushed at this acceleration. Therefore the ratio would be 1/7. Is this correct?

2. Sep 15, 2014

BiGyElLoWhAt

Have you tried drawing a freebody diagram? I think that would help in this case. On the first block you obviously have tom pushing up. Is that it? You can repeat this for all the blocks.

3. Sep 15, 2014

The Wanderer

Yeah I tried that.... but I don't think I am doing it correctly haha.
The blocks are lying on the table and he is exerting a horizontal force on block 1 causing all of them to move.

They way I thought of doing a freebody diagram is that the forces on 1 is the force from book 2 and Tom. Then on 2 you have the force from book 1 and the force from book 3. And then for 3 you have the force from book 2 and book 4.

But thinking about that again and wouldn't the boxes not push back on each other because the table is a frictionless surface? The force exerted by book 2 onto 1 is generated by there being friction. So my second guess is the only force on any blocks are the forces inbetween the two blocks. So force exerted on block 1 is just Tom. Force on block 2 is the force exerted by block 1. Force on block 3 is the force exerted by block 2 and so on. But then wouldn't the force just be equal to Tom's force once you iterated through all of that? Or should the force acting on block 2 be Tom and the force exerted by block 1?

4. Sep 15, 2014

PaulDirac

Hint: Using the Newton's second and third laws you can write 8 separate equations. Add up all of this 8 equations to get the force F exerted to the first block.bI think it is 8ma, where a is the same acceleration for all bodies; since they are moving at the same constant rate of change of speed. Using the first equation you can obtain the force F12 which should be 7ma. Using this and the last equation you can come up with the ratio that should be 7.

5. Sep 15, 2014

The Wanderer

OHHH. So the force exerted from block two to block one is equal to the 7 masses of the blocks just sitting there * acceleration. And then the force from the last block only has one block to push against so its just m*a. My logic was just really bad on this problem haha thank you very much.