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2.00 m to the ground below. Assume that the force of the

ground on his feet is constant.

Compute the force of the ground on his feet if he

jumps stiff-legged, the ground compresses 2.00 cm,

and the compression of tissue and bones is negligible

solution:

F = (4.00*10^2/9.8)(9.8) + (4.00*10^2) = 800

answer is 4.04 *10^4 N