Force problem

  • Thread starter Miike012
  • Start date
  • #1
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A boy weighing 4.00 *10^2 N jumps from a height of
2.00 m to the ground below. Assume that the force of the
ground on his feet is constant.
Compute the force of the ground on his feet if he
jumps stiff-legged, the ground compresses 2.00 cm,
and the compression of tissue and bones is negligible

solution:

F = (4.00*10^2/9.8)(9.8) + (4.00*10^2) = 800
answer is 4.04 *10^4 N
 

Answers and Replies

  • #2
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Could I use the formula

Wnc = ΔE ?
 
  • #3
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Nevermind I got it
 

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