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Force problem

  1. Nov 28, 2011 #1
    A boy weighing 4.00 *10^2 N jumps from a height of
    2.00 m to the ground below. Assume that the force of the
    ground on his feet is constant.
    Compute the force of the ground on his feet if he
    jumps stiff-legged, the ground compresses 2.00 cm,
    and the compression of tissue and bones is negligible

    solution:

    F = (4.00*10^2/9.8)(9.8) + (4.00*10^2) = 800
    answer is 4.04 *10^4 N
     
  2. jcsd
  3. Nov 28, 2011 #2
    Could I use the formula

    Wnc = ΔE ?
     
  4. Nov 28, 2011 #3
    Nevermind I got it
     
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