A sailor tests the tension in a wire rope holding up a mast by pushing against the rope with his hand at a distance L from the lower end of the rope. When he exerts a 'transverse' push N, the rope suffers a transverse displacement s.
Show that for s << L, the tension in the wire rope is given approximately by the formula:
T = N L/s
The Attempt at a Solution
I looked up the word transverse and it meant to be perpendicular. So, then we have that the tension vector, and the displacement vector and another side make a right angle triangle. Then, T is the hypotenuse of the triangle displacement^2 + another side^2.. I know that if I can get a proper sine or cosine equation, I can use the opp/hyp identities to come to that solution, but I can't see it.. thanks