Here is the question: I have attached the picture of the situation and below is how I tried to solve it. Block A: mass = 4 kg - given the normal force = 34 N - normal force = m*g*cos(angle) the force (parralell to the ramp surface) fulling it down =19.62 N - force paralell = normal force * sin (angle) no frictional force Block B: mass = 2 kg - given normal force = 19.62 N - formal force = m*g coefficent = kennetic friction = .5 - given force of kinetic friction = 9.81 N - force of friction = normal force * coefficient of friction so now there is a 19.62 N force pulling the blocks down, and a 9.81 N force trying the pull block B back, so as I see it, the tension in the cord is equal to 16.62-9.81 = 9.81 N. and then since there is a 9.81 N force acting on both blocks, the acceleration = net force / total mass = 1.64 m/s^2. I got the acceleration correct, says the book, but not the tension force. If I look in the backl of the book, it gives me the answer, which is not what I calculated. A. Tension in the cord = 13 N B. Acceleration = 1.6 m/s^2 ___I got this one right I would really like to understand how to do this problem correctly.