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Force Required to lift

  1. Apr 10, 2004 #1
    I want to know how to calculate the amount of force req. in the given picture. I want to lift the load 3 meters high.

    Can any one help.

    Attached Files:

    Last edited: Apr 12, 2004
  2. jcsd
  3. Apr 10, 2004 #2
    Where is the picture?
  4. Apr 10, 2004 #3
    I attached it in the thread
    Dont know how to use it


  5. Apr 10, 2004 #4
    I can't see how you can lift the load 3 meters high when the lever connected to it is just 1 meter long. Or do you mean "throwing" the load 3 meters high, rather than lifting it while it's on the lever?
  6. Apr 10, 2004 #5
    You got it right my friend

    The ball / load is not attached to the arm.

    Hence the ball needs to be thrown upwards.
  7. Apr 10, 2004 #6
    You have given us a point of application, but no direction or sense.
  8. Apr 12, 2004 #7

    I have changed the image for your ref.

    please help me how to calculate the req. force whith the given angle and also if you change the angle.

  9. Apr 12, 2004 #8


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    Homework Helper

    You need to apply energy, not force (they are related, but it will be easier to first consider the required energy, and then translate that into how much force to apply).
  10. Apr 13, 2004 #9
    Thanks TURIN

    But in that case u will need to tell me how to find energy and then how to convert it to force.

  11. Apr 13, 2004 #10
    Generally speaking, the work done by all non-conservative forces is equal to the change in mechanical energy of the object. In your case:

    [tex]{W_F}_{ext} = \Delta E_m = \Delta E_k + \Delta E_p[/tex]

    Since the inital velocity and final velocity are both zero, there is no change in kinetic energy so it comes down to this:

    [tex]W_F = \vec F\cdot \vec x = mgh[/tex]
  12. Apr 13, 2004 #11


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    And don't forget that the x vector has a maximum value (determined by the lever arm).
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