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I've worked out (i), having problems with (ii). I know that the torque will be force x 0.75 but I haven't had any success in working out the force in the first place.

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- Thread starter smr101
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- #1

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I've worked out (i), having problems with (ii). I know that the torque will be force x 0.75 but I haven't had any success in working out the force in the first place.

- #2

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What's the force required to accelerate the wagon if there's no incline?

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What's the force required to accelerate the wagon if there's no incline?

Without an acceleration, I'm not sure.

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From the problem statement, "... accelerate the wagon from rest to 2.6 m/s over a distance of 8.2 m at constant acceleration ...."Without an acceleration, I'm not sure.

- #5

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From the problem statement, "... accelerate the wagon from rest to 2.6 m/s over a distance of 8.2 m at constant acceleration ...."

Right I've got the acceleration but I'm not getting the correct force. You're saying the force needed to work out the torque is when there is no incline?

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No. You've got the force to do the acceleration? Can you calculate the force necessary to move the wagon up the incline? Add them.when there is no incline?

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No. You've got the force to do the acceleration? Can you calculate the force necessary to move the wagon up the incline? Add them.

F = ma

= 1920 x 0.41

= 787.2

Fw = mgsinangle

= 1920 x 9.81 x sin10

= -10246.7

- #8

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Don't just punch numbers into a calculator and blindly accept the number that comes out. What's the sin of 10°?= 1920 x 9.81 x sin10

= -10246.7

- #9

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Don't just punch numbers into a calculator and blindly accept the number that comes out. What's the sin of 10°?

Ah, I was in radians...

Fw = mgsinangle

= 3270.7

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Better.

- #11

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Better.

Then just add the Ff to that and the Fu I've got it... Thanks, I've made that much more difficult than it should have been!

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