- #1
wku_tops
- 8
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Please look at this pic for the problem. http://thumb5.webshots.com/t/57/757/4/82/60/2732482600078932085VPLQzD_th.jpg
I have drawn the freebody diagrams correctly.
http://thumb5.webshots.com/t/53/453/3/64/60/2611364600078932085NMvdfG_th.jpg
http://thumb5.webshots.com/t/53/453/3/64/60/2611364600078932085NMvdfG_th.jpg
I solved for F' to be 14.07 N, but I can't solve Fr. I think the key to the problem is the law of sines. According to autocad the angle opposite Fr is 13 degrees, but how do I solve for that myself without autocad?
Here's some work I've done:
90-20=70 degrees
F’2=(50 N)2 + (20 N)2 -2(50 N)(20 N)cos(70)
F’=47.07 N
47.07 N 50 N
----------= -------- Θ=86.46 degrees
Sin 70 sin Θ
90-86.46= 23.53 degrees
I have drawn the freebody diagrams correctly.
http://thumb5.webshots.com/t/53/453/3/64/60/2611364600078932085NMvdfG_th.jpg
http://thumb5.webshots.com/t/53/453/3/64/60/2611364600078932085NMvdfG_th.jpg
I solved for F' to be 14.07 N, but I can't solve Fr. I think the key to the problem is the law of sines. According to autocad the angle opposite Fr is 13 degrees, but how do I solve for that myself without autocad?
Here's some work I've done:
90-20=70 degrees
F’2=(50 N)2 + (20 N)2 -2(50 N)(20 N)cos(70)
F’=47.07 N
47.07 N 50 N
----------= -------- Θ=86.46 degrees
Sin 70 sin Θ
90-86.46= 23.53 degrees
Last edited: