- #1

godplayer

- 10

- 0

The Graph

For the first two seconds there is a force of 6.0N. The the force decreases linearaly to 0N at 4 seconds. How do I find the velocity of the object at 4.0 seconds?

I got the velocity at 2 seconds by using F=ma and solving for a:

6.0=2.0a

a=3

With that acceleration I then found:

V=Vi+at

V=0+(3)(2)

V=6

I just don't know how to get the rest.