(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 1600kg jet engine is fastened to the fuselage of a passenger jet by just three bolts (this is the usual practice). Assume that each bolt supports one-third of the load.

(b) During flight, the plane encounters turbulence, which suddenly imparts an upward vertical acceleration of 2.8 m/s2 to the plane. Calculate the force on each bolt now.

2. Relevant equations

F = ma

3. The attempt at a solution

The force acting on the engine is the sum of all forces acting on the engine because of Newton's second law. So first I found the force of gravity on the engine

F=ma

F=1600(9.8)

F=15,680 N

then I found the force the turbulence had on the engine

F=1600(-2.8)

F= -4480 N

Then the sum of these forces is -4480 + 15,680 = 11,200

Then I divided this by 3, for the force on each bolt and got 3,733 N.

But when I typed this answer in it was not correct and I do not know what I am doing wrong.

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# Homework Help: Forces acting on a jet engine

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