Forces and acceleration

  • Thread starter Jamotron
  • Start date
  • #1
2
0
A simple problem from a list of many I was working through as revision:

Homework Statement


Two ropes are attached to a 40kg object. The first rope applies a force of 45 N, and the seond 40 N. If the two ropes are perpendicular to each other, what is the resultant acceleration?
a)1.2m/s2
b)3.0m/s2
c)25m/s2
d)47m/s2

Homework Equations


F=ma
F1x=F1cos theta1
F2x=F2cos theta2

F1y=F1sin theta1
F2y=F2sin theta2

a=(ax2+ay2)1/2

The Attempt at a Solution


As the angles of ropes to the object are not given but the ropes are stated as being perpendicular I took 45 degrees as the angle of both ropes, which gives me the same answer for Fx and Fy which is49.45N. Therefore:
ax=Fx/M = 1.23m/s2
ay=Fy/M=1.23m/s2
Now, this value is consistent with answer a) given in the question. However I was under the impression that to find the magnitude of the acceleration I need to use the equation
a=(ax2+ay2)1/2. As I've figured the x and y acceleration to be equal this will give me a =1.74 m/s2.

So where have I gone wrong? What would be the correct procedure for solving this problem? I'm very new to physics so any help would be appreciated :)
 

Answers and Replies

  • #2
2
0
Anybody out there able to help at all???
 
  • #3
It does not matter what angle you are considering as the magnitude of acceleration will be same (if no other force such as gravity are being considered). Hence just use Pythagoras theorem.

And do not be impatient. Members here are able to solve question much more difficult than this. Do not question the ability, in future.
 

Related Threads on Forces and acceleration

  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
1
Views
446
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
2
Views
868
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
6
Views
1K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
12
Views
5K
Top