# Forces and Inclines

1. Jan 5, 2010

### seizureboi

1. The problem statement, all variables and given/known data

A 3kg block is pulled by a rope up a 37 degree incline at constant speed. If the tension in the rope is 45N and the rope is parallel to the incline, calculate the coefficient of kinetic friction between the block and the incline.

2. Relevant equations

a = acceleration (0 m/s2)
Ө = theta (37 degrees)
g = 9.8 m/s2
m = mass
T = Tension
μ = coefficient of friction
NF = Normal Force
friction = μNF
NF = mgcosӨ

3. The attempt at a solution

My attempt was setting up the equation: TsinӨ - mgsinӨ - friction = ma
OR 45sin(37) - (3)(9.8)sin(37) - μ(3)(9.8)cos(37) = 0
OR 27.1 - 17.7 = μ23.5
OR 9.4 = μ23.5
Finally, μ = .4

Just wondering if it's correct. =)

2. Jan 5, 2010

### jegues

You don't need a sinӨ multiplying the tension, the force of the tension is given parallel to the plane so you wouldn't need to factor an angle in, make sense?

3. Jan 5, 2010

### seizureboi

Cool, because I did try it that way and i got μ = 1.16 and I thought I was wrong so I concluded with adding a random sinӨ lol.