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Forces, newton's law problem

  1. Jul 25, 2011 #1
    Air rushing over the wings of high-performance race cars generates unwanted horizontal air resistance but also causes a vertical downforce, which helps the cars hug the track more securely. The coefficient of static friction between the track and the tires of a 690-kg race car is 0.87. What is the magnitude of the maximum acceleration at which the car can speed up without its tires slipping when a 4060-N downforce and an 1190 N horizontal air resistance force act on it.

    My work:

    I get the general concept of the problem, but my confusion is about 1/2 way into the problem.

    The free-body diagram would be like so:
    The car is moving in the positive direction, +x.
    Frictional force and air resistant point in the negative direction, -x.
    Normal force points up.
    Weight and downward force point down.


    GIVEN
    coefficient of friction, u = 0.87
    m = 690 kg
    w = 690(9.8) = 6762 N
    Downforce, Fd = 4060 N
    Air resistance, Fa = 1190 N

    Normal Force = Fn = 6762 + 4060
    Normal Force = Fn = 10, 822 N

    Force of friction = Ff = (Fn)(u)
    Ff = (10822)(0.87)
    Ff = 9415.14 N

    We know that frictional force is in the -x direction.

    Net Fx = -Fa + (-Ff) = ma
    Net Fx = -1190 + (-9415.14) = (690)a *************
    a = (-10605.14) / 690
    a = -15.369768 m/s^2

    My teacher said that I messed up at the part with the stars. He says that there shouldn't be a negative sign infrom of the Ff, force of air resistance.

    Isn't frictional force a vector that points in the -x direction? Could somebody please explain this to me please? Does the frictional force of a tire point in the positive direction? And if yes, is this always true for tires? and lastly, are there other instances besides tires where this is the case? Thank you in advance !!! :]
     
    Last edited: Jul 25, 2011
  2. jcsd
  3. Jul 25, 2011 #2
    hey jehan4141

    If the car is moving in +x then friction due to downward forces and air drag should act in -x

    if this wasn't true and air drag should be in +x so we can design a car for which air drag>downward force friction and then that car will move on its own ... which is not possible

    so air drag should be in -X IMO
    ask your teacher again in case he told you this by mistake
     
  4. Jul 25, 2011 #3
    thank you :) i will ask him again :D
     
  5. Jul 25, 2011 #4
  6. Jul 25, 2011 #5

    gneill

    User Avatar

    Staff: Mentor

    In order for the car to accelerate in the +x direction, its tires must push back against the road surface, in the -x direction. The force that prevents the tire from slipping is the static friction. So the static friction must act in the +x direction (thus opposing the tire's backwards push in the road surface).
     
  7. Jul 26, 2011 #6
    OH MY GOD !!!

    I forgot that tires are rolling ... Damn it that was a dumb mistake ...
    ______________

    jehan, I am really sorry for the wrong answer ... :(

    Thank you gneill for correcting me.
     
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