1. The problem statement, all variables and given/known data http://www.webassign.net/CJ/04_75.gif A cable is lifting a construction worker and a crate, as the drawing shows. The weights of the worker and crate are 922 and 1500 N, respectively. The acceleration of the cable is 0.620 m/s2, upward. (a) What is the tension in the cable below the worker? 1594.9 N (b) What is the tension in the cable above the worker? 2. Relevant equations Force = mass x acceleration weight = mass x g 3. The attempt at a solution (a) What is the tension in the cable below the worker? 1594.9 N (b) What is the tension in the cable above the worker? I have figured out part a, here is my work: Since it is accelerating upward, force of tension is greater than the weight. 1500 N = mass x 9.8 m/s^2 mass = 153.1 kg acceleration = 0.620 m/s^2 FT - 1500 = 153.1(0.620) FT = 1594.9 N I used this same method for B, but the answer is wrong. How do I get the tension of the cable above the worker? Thanks a bunch in advance.