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Forces of pulleys

  1. Jun 24, 2014 #1
    1. The problem statement, all variables and given/known data
    Calculate the tension in the cable connecting the two masses. Assume all surfaces are frictionless.

    http://tinypic.com/r/20jg36s/7

    2. Relevant equations



    3. The attempt at a solution
    I tried to begin the solution but came out with a negative acceleration (-2m/s^2)
    For the 5 kg mass:
    Ft-Fg2sin60=ma
    Ft-(5)(9.8)sin60=5a
    Ft-49sin60=5a
    I wasn't sure how to get the equation for the 6 kg mass...
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jun 24, 2014 #2

    Orodruin

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    Why would the equation for the 6 kg mass be more difficult than that of the 5 kg one? The same principles apply. Just make sure you relate the string tensions and accelerations properly according to your conventions and you should be able to solve it.
     
  4. Jun 24, 2014 #3
    But I'm on the right path here?
     
  5. Jun 24, 2014 #4
    Get Fg1 * sin(60 degrees) and Fg2 * sin(70 degrees) and then determine the magnitude and direction of the tension force.
     
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