# Forces on a Bike

Q. A biology student rides her bike around a corner of radius 24 meter at a steady speed of 8.3 m/sec. The combined mass of the student and the bike is 87 kg. The coefficent of static friction between the bike and the road is μs = 0.39.

What is the magnitude of the total force between the bike tire and the road?

Is it F = umg + mv^2 / R [ 'u' here is the static firction 0.39 ]

Is this right.

dextercioby
Homework Helper
No.The friction force is centripetal force...It prevents slipping.So what are the forces involved there...?

Daniel.

Force of gravity and Normal force, what else can it be?

dextercioby
Homework Helper
There must be 3:what about the friction force...?

Daniel.

Ok, I agree 3 forces,

but the final eqn,

would it be something like this:

mg + mv^2/R +Us.mg

OlderDan
Homework Helper
Forces are vectors. Any addition of forces in this problem is going to involve vector sums.

Centripetal acceleration has to come from somewhere. The equation that tells you how big it must be, does not tell you what provides the force. Two of the forces in your equation are the same force.

dextercioby