Suppose that you're on a circular ferris wheel with a radius of 22 m. You know that your mass is 64 kg on the very bottom part of the ferris wheel, even though your actual mass is 58 kg. How long does it take for the ferris wheel to go one revolution?
I believe centripetal force? F = mv^2/r
Gravitational force: F = mg
Circumference: C = 2*pi*r
The Attempt at a Solution
So, what I did was set the centripetal force equal to the gravitational force:
mv^2/r = mg
v = Sqrt[g*r] which gave me the value 14.6 m/s. I then found the circumference of the ferris wheel to be 2*pi*22 = 138.23 m, and used the relation t = displacement/velocity to obtain 9.41 s.
This, however, came out to be wrong... is my problem setup incorrectly?