A lemon has three horizontal forces that act on it as it is on a frictionless table. Force F1 has a magnitude of 4.50 N and is at Angle1 = 26°. Force F2 has a magnitude of 7.00 N and is at Angle2= 26°. The lemon half has mass 0.0250 kg. Picture is Attached. What is the third force if the lemon half has the following velocities? I did f1=4.5cos26i + 4.5sin26j f2=7cos(-64)-7sin(-64) THen I did f=(4.5cos26+7cos(-64))i+(-7sin(-64)+4.5sin36)j=7.11i+(-4.32j) (a)At Zero velocity i got the I component to be -7.11 and the j component to be 4.32. The j component is right but the i component is wrong and I don't know why. (b)constant velocity v = (13.0 i - 14.0 j) m/s (c) varying velocity v = (13.0t i - 14.0t j) m/s, where t is time in seconds What would I do to solve for B and C?