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Forces on particles

  1. Oct 8, 2007 #1

    ~christina~

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    Gold Member

    1. The problem statement, all variables and given/known data

    3 of 4 Forces acting on a 10kg mass in free space are shown in figure below.

    a) Express these forces in unit vector notation

    b) Find the magnitude and direction of the fourth force F4 so that the particle maintains a constant velocity of 15m/s

    c) Express F4 in unit vector notation
    [​IMG]

    2. Relevant equations
    F=ma??

    3. The attempt at a solution

    a)

    F1= 10N(cos 60i - sin 60j)= 5.00i- 8.66j

    F2= 3N(cos 90i + sin 90j)= 3j

    F3= 4N(-cos 20i- sin 20j)= -3.76i- 1.37j

    b) F4= F1 + F2 + F3

    F4= 5.00i - 8.66j + 3j - 3.76i - 1.37j= 1.24i - 7.03j

    direction:
    tan(theta)= y/x = -7.03/1.24= -5.6693
    tan^-1(-5.6693)= -79.997

    theta= -79.997 deg

    magnitude:
    F4= [tex]\sqrt{} (1.24)^2 + (-7.03)^2[/tex]= 7.14N

    F4= 7.14N, -79.997 deg


    I'm not sure how do I know if the magnitude and direction of the mass (strangely they now describe the mass as a particle) is maintaining a constant velocity of 15m/s?

    c) for vector notation of F4 wouldn't it be

    F4= 7.14N
    theta= -79.997

    x= F4 cos (theta)
    y= F4 sin (theta)

    x= 7.14 cos(-79.997) = 1.24i

    y= 7.14 sin ( -79.997) = -7.03j

    F4= 1.24i- 7.03j

    ~this is the same as before I converted it to cartesian coordinates...so Is this fine or is the previous part c have to do anything with the answer for d?
    I didn't know what they wanted for b so I just converted the answer for c that I got without taking into account the 15m/s velocity requirement...


    Do I need to use F= ma?? this wouldn't make sense b/c there is no place for velocity in the equation...


    Help please..

    Thank you =)
     
  2. jcsd
  3. Oct 8, 2007 #2

    Astronuc

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    Staff: Mentor

    Part a seems correct.

    In order for the mass to move at constant velocity, it must have no net force acting on it, so F4 must act with equal magnitude, but opposite (direction) to the resultant (sum) of force F1 + F2 + F3.

    F = ma is not necessary for this problem. For constant velocity a = 0.
     
  4. Oct 8, 2007 #3

    ~christina~

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    Gold Member

    since F1 + F2 + F3= F4=
    but theta would equal -79.997 + 180= 100.003 deg

    c.) I would then I guess just convert it to vector unit notation.

    where
    x= 7.14(cos 100.003)= -1.24i
    y= 7.14(sin 100.003)= 7.03j

    F4= -1.24i + 7.03j


    I think this is fine right? Just making sure =D

    Thanks Astronuc =)
     
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