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Forces question

  1. Mar 4, 2006 #1
    with reference to the diagram, at what angle must the 800N force be applied in order that the resultant R of the two forces has a magnitude of 2000N.

    We were instructed to use the i,j method.

    So, the forces for Fi = 800sin(-) and Fj = 1400 + 800 cos(-) and the resultant is 2000N.

    This is where i get stuck, a^2 + b^2 = c^2
    so 2000^2 = (800 sin(-))^2 + (1400+800 cos(-))^2

    any help would be great.
     

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  2. jcsd
  3. Mar 5, 2006 #2
    bump^

    please help :p
     
  4. Mar 5, 2006 #3

    Hootenanny

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    We can't see the attachment yet...
     
  5. Mar 5, 2006 #4
    it is simply a diagram showing

    |........./
    |......./
    |(-)./
    |.../
    |./

    with the verticle line saying 1400N and the diagonal line saying 800N
     
  6. Mar 6, 2006 #5

    mukundpa

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    It appears correct, expand

    2000^2= 800^2 sin^2(@) + 1400^2 +2*1400*800*cos@ + 800^2*cos^2@

    2000^2 - 800^2 - 1400^2 = 2*1400*800*cos@

    solve for cos@


    MP
     
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