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Forces question

  1. Dec 7, 2009 #1
    1. The problem statement, all variables and given/known data
    A block of mass 8.0kg starting from rest is pulled along a rough horizontal tabletop by a constant force of 2N it is found that the block moves a distance of 3.0m in 6 seconds
    a) what is the acceleration?
    b) What is the net force acting on the block?

    2. Relevant equations
    Fnet = Ma

    3. The attempt at a solution
    v = d/t
    v = 3/6
    v = 0.5m/s
    a = v/t
    a = 0.08m/s^2
    Fnet = 8 x 0.08
    = 0.64N [F]
  2. jcsd
  3. Dec 7, 2009 #2


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    Homework Helper

    You can't use v = d/t when the motion is accelerated.
    Use formulas with acceleration in them.
    d = Vi*t + .5*a*t² should work well.
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