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Forces question

  1. Dec 9, 2009 #1
    1. The problem statement, all variables and given/known data
    A boy puts a 250kg elephant on a piece of carpeting and slides it across the floor by exerting a horizontal force of 425N on the elephant



    2. Relevant equations
    Ff = uKFn


    3. The attempt at a solution
    Fn = Fg
    Fnet = Fap - Ff
    Fnet = 425 - Ff
    ma = 425 - uKFn
    250a = 425 - uK(2450)
     
  2. jcsd
  3. Dec 9, 2009 #2

    itr

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    what is the question asking?
     
  4. Dec 9, 2009 #3
    for coefficient of kinetic friction
     
  5. Dec 9, 2009 #4

    itr

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    mue=f max/fn
    425N/(250x9.81)
    mue=.173

    I believe thats how you do it
     
  6. Dec 10, 2009 #5
    why is friction 425N
     
  7. Dec 10, 2009 #6

    itr

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    its force
     
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