Forces question

1. The problem statement, all variables and given/known data
A boy puts a 250kg elephant on a piece of carpeting and slides it across the floor by exerting a horizontal force of 425N on the elephant



2. Relevant equations
Ff = uKFn


3. The attempt at a solution
Fn = Fg
Fnet = Fap - Ff
Fnet = 425 - Ff
ma = 425 - uKFn
250a = 425 - uK(2450)
 

itr

43
0
what is the question asking?
 
for coefficient of kinetic friction
 

itr

43
0
mue=f max/fn
425N/(250x9.81)
mue=.173

I believe thats how you do it
 
why is friction 425N
 

itr

43
0
its force
 

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