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## Homework Statement

Billy has caught two fish. He has tied the line holding the 4.40kg trout to the tail of the 2.36kg carp. To show the fish to a friend, he lifts upward on the carp with a force of 71.3 N. What is the tension of the rope connecting the trout and carp?

## Homework Equations

Fy=ma,

## The Attempt at a Solution

m=(mCARP+mTROUT), FA=applied force, FT=force of tension

Carp:

Fy=ma

FA-mg-FT=ma

71.3-(2.36+4.40)(9.8)-FT=(2.36+4.40)a

5.052-FT=6.76a

a=(5.052-FT)/6.76

Trout:

Fy=ma

FT-mg=ma

FT-(2.36+4.40)(9.8)=(2.36+4.40)a

FT-66.248=6.76a

a=(FT-66.248)/6.76

a=a, so:

(5.052-FT)/6.76= (FT-66.248)/6.76

5.052-FT=FT-66.248

5.052+66.248=FT+FT

71.3=2FT

FT=35.65N=35.6N

***My online assignment says that this answer is wrong***