In the Ford F150 commerical that debuted during the Superbowl (), Ford says that it subejcted the tow hooks on the truck to 6g's of force. I timed the period of the truck during the portion in which the narrator is visible on the screen and got 1.80 seconds roughly. I read online that the truck was swung in a 50 foot circle (http://www.the-signal.com/?module=displaystory&story_id=53067&format=html) If I use a radius of 25 feet (7.62 meters) for the circle and a period of 1.80 seconds and use v=2(pi)(r)/T I find that the truck goes approximately 27 m/s (60 mph as the article claims). If I then use a = v^2/r to get the centripetal accleration, I find that the acceleration is 96 m/s^2. 96 m/s^s is more like 10g's, not 6 g's. Am I doing something wrong?