# Forklift problem

1. Mar 5, 2005

### nineeyes

I attached the problem and diagram.

This problem has been bothering me a bit. A friend of mine told me I could solve for the stopping distance by just looking at the crate.
I got
x: $$\mu*N_w = M*a$$
y: $$N_w-W_w=0$$
and from this got
$$a=-9.66\frac{ft}{s^2}$$

I used the acceleration and given inital velocity of 10 ft/s and final velocity of 0 ft/s and solved for the stopping distance through

$$s=\frac{-v_0^2}{2*a}$$

Assuming I approached this correctly, I wasn't sure how to check if it doesn't tip. I thought that I could just take the moment about a point and solve for $$N_B$$, I did

$$\sum M_A=N_B*7-W_G*4+W_W*3-a*3=0$$
and got

$$N_B=210.15$$ lbs. $$\therefore$$ it does not tip

Is that right? I also was wondering if I have to consider frictional force in the moment equation.