Form factor

  • #1
malawi_glenn
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I have a form factor that only depends on the momentum transfer q, this is symbolised by writing the form factor as F(B]q[/B]^2).

attachment.php?attachmentid=9529&stc=1&d=1174375818.jpg


if i have a spherical symmetric distribution of charge, f only depends on the radius; r = | q|

Then integration over all solid angels yields:

https://www.physicsforums.com/attachment.php?attachmentid=9530&stc=1&d=1174376003

(there should be a r^2 inside the integral ;))

I do not understand how this Sinus - thing plops up.. all i know is this:
https://www.physicsforums.com/attachment.php?attachmentid=9531&stc=1&d=1174376117

I really need a hint how to go from the exponential function to this sinus thing. =/
 

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Answers and Replies

  • #2
Dick
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Since f(x) is independent of the polar angles you can rotate the x coordinate system so that the q vector points along, say, the positive z-axis. So the exponential becomes exp(i*|q|*r*cos(theta)). Doing the theta integration gives you the 'sinus thing'.
 
  • #3
malawi_glenn
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thanx alot, i will try tonight:)
 
  • #4
malawi_glenn
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it was a piece of cake now, thanx again!
 
  • #5
2
0
Could you explain more about it?
 

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