can someone explain what the formal difinition of a limit ?
n -> [oo] An < +/- [oo]
the limit as x tends to a of f(x) equals L if;
for every number epsilon (usually, cant find the symbol) > 0, there is a corresponding number [sig] > 0, such that for all x;
0 < |x-a| < [sig] ==> |f(x) - L| < epsilon.
Is the formal definition.
for example (easy one);
To show that the limit of 5x - 3 as x tends to 1 is actually 2;
so a = 1, L = 2 (since this is what it does appear to converge to). Need
0 < |x-1| < [sig] for any epsilon > 0.
f(x) is within epsilon of L ie. |f(x) - 2| < epsilon. So to find [sig] from this,
|(5x-3) - 2| = |5x - 5| < epsilon
5|x - 1| < epsilon
|x - 1| < epsilon / 5.
so [sig] = epsilon / 5
and from 0 < |x - 1| < [sig] = epsilon / 5,
|(5x - 3) - 2| = 5 |x - 1| < 5 (epsilon / 5) = epsilon.
Which proves that L = 2.
Alternatively find a good text book
The limit definition looks rather convulated when stated in terms of epsilons and deltas. One good way of thinking about it is this:
Given any allowable magnitude of error (formally epsilon) from a value (the limit), there exists a range near c (the value x is approaching) for which the function's outputs ( f(x) ) will deviate from the limit no more than the given magnitude of error (epsilon).
The key here is that if the limit for f(x) at a particular point c exists (and hence the previous statement holds), then we are stating that we can get f(x) as close to L as we want. I can make it within .001 or .000001, ... anything (because for each error I present to it, the limit existing garuntees that i can find an interval of values for x symmetrically about c such that f(x) will be that close to L).
Separate names with a comma.