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Formula developing

  1. May 22, 2010 #1
    [tex]0=q\mu \bar{n}E-qD_e\frac{d\bar{n}}{dx}\\[/tex]
    [tex]\frac{{}D_e\frac{d\bar{n}}{dx}}{\mu \bar{n}}=E\\[/tex]
    [tex]v=-\int_{x_n}^{x_p}Edx=-\int_{x_n}^{x_p}\frac{{}D_e\frac{d\bar{n}}{dx}}{\mu \bar{n}}dx=-\int_{x_n}^{x_p}\frac{{}D_e\d\bar{dn}}{\mu \bar{n}}\\[/tex]

    they say some thing about einshtein
    why Dn/[tex]\mu[/tex]=kt/q??
    so we see that dx and 1/dx eliminate each other so its not and integral anymore
    we dont have dx

    and i dont know how from this point they get??
    [tex]\frac{kt}{q}\ln p |^{x_p}_{x_t}=\frac{kt}{q}\ln\frac{{}{N_AN_D}}{n_i^2}
    where the put x_p and x_n in the integral
    wht is our variable
  2. jcsd
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