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Formula for average force?

  1. Dec 9, 2007 #1
    [SOLVED] Formula for average force?

    In a ballistics test at the police department, Officer Rios fires a 6.0 g bullet at 350 m/s into a container that stops it in 1.8 ms. What is the average force that stops the bullet?

    can anyone help me to do this? or just give me the formula? The teacher gave us the right answer and it's -1.2 x 10^3N
     
    Last edited by a moderator: Dec 18, 2007
  2. jcsd
  3. Dec 9, 2007 #2

    nicksauce

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    The average force is the change in momentum divided by the change in time.
     
  4. Dec 9, 2007 #3
    This is just an impulse-momentum theorem problem. Impulse = Change in momentum. Impulse is F*delta t (t=time of impact) and change in momentum is just final momentum - initial momentum. Good luck
     
  5. Dec 9, 2007 #4
    delta p= J
    and J= F(delta t)

    so

    delta p=6.0g(350m/s)
    delta p=2100
    2100/1.8=1166.6666667

    is that the same thing as 1.2x10^3?
     
  6. Dec 9, 2007 #5

    cristo

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    It would be rounded to 1.2x10^3, yes.
     
  7. Dec 9, 2007 #6
    thank you so much guys!
     
  8. Dec 9, 2007 #7

    cristo

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    You're welcome (I'll speak on behalf of the people that actually helped you! :smile:)
     
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