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[tex]a = \frac{v^2}{r}[/tex]

toward the center of the circle.

cookiemonster

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- Thread starter cookiemonster
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- #1

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[tex]a = \frac{v^2}{r}[/tex]

toward the center of the circle.

cookiemonster

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HallsofIvy

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The point of cookiemonster's formula is that you want to make

a equal to g: 9.81 m/s^{2}. v is, of course, the linear speed. For a circle of radius R, so circumference 2πR, moving with RPM ω, &omega revolutions per minute means covering 2πωR meters per minute or 2πωR/60= πωR/30 meters per second. That is: v= πωR/30 where v is in m/s and &omega is RPM. In terms of RPM, then

[tex] a= \frac{v^2}{R}= \frac{\pi^2\omega^2R^2}{900R}= \frac{\pi^2\omega^2R^2}{900}= 9.81\frac{m}{s^2} [/tex]

Plug in 7.5 for R and solve for ω

a equal to g: 9.81 m/s

[tex] a= \frac{v^2}{R}= \frac{\pi^2\omega^2R^2}{900R}= \frac{\pi^2\omega^2R^2}{900}= 9.81\frac{m}{s^2} [/tex]

Plug in 7.5 for R and solve for ω

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Oh, did I just make myself a nitpicker?

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